/*
    switch.c
    Tanya Amert, Fall 2023

    How do switch statements get represented in x86-64?

    Compile for debugging via gdb:

        gcc -g -Og -o switch switch.c

    Run with one command-line argument (which case):

        ./switch 3
*/
#include <stdio.h>
#include <stdlib.h>

int switch_f(int val)
{
    int result = 0x314;

    switch (val)
    {
        case 0:
            result -= 1;
            break;

        case 1:
            result *= 2;
            break;

        /* no case 2 -- default instead */

        case 3:
            result += 4;
            /* fall through to case 4 */

        case 4:
            result -= 0xa0;
            break;

        /* no case 5 -- default instead */

        case 6:
            result *= 3;
            break;

        default:
            result += 0x10f;
            break;
    }

    return result;
}

int if_f(int val)
{
    int result = 0x314;

    if (val == 0)
    {
        result -= 1;
    }
    else if (val == 1)
    {
        result *= 2;
    }
    else if (val == 3)
    {
        result += 4;
        result -= 0xa0;
    }
    else if (val == 4)
    {
        result -= 0xa0;
    }
    else if (val == 6)
    {
        result *= 3;
    }
    else
    {
        result += 0x10f;
    }

    return result;
}

int main(int argc, char *argv[])
{
    if (argc != 2)
    {
        printf("You need to give a number.\n");
        exit(0);
    }

    // Convert the input number to an int
    int val = atoi(argv[1]);

    int result = switch_f(val);
    printf("Result: %d\n", result);

    return 0;
}