To disprove a statement of the form "if P then Q", you need to provide a counter-example. That is, you find something for which P is true, but Q is false. For example, the first statement below (which is false) has P = "G has N vertices and at least N-1 edges" and Q = "G is connected." Your job is to find a particular graph with N vertices (any N will do) and at least N-1 edges that is not connected. Such a graph would make P true but Q false, thus disproving "P ==> Q".
Have fun.
Draw the cube's graph on a sheet of paper with no edge crossings. Do the same for the cube's dual graph, the tetrahedron, the tetrahedron's dual graph, the octohedron, and the octohedron's dual graph (don't know what an octohedron is? find someone who plays Dungeons and Dragons to show you an 8-sided die, or come to class Monday and ask me).
What can you say about the duals of the octohedron, the cube, and the tetrahedron? Aren't you glad I didn't ask you about the dodecahedron (12 sides) and the icosahedron (20)?